2x^2-100x-1000=0

Solution for 2x^2-100x-1000=0 equation:

2x^2-100x-1000=0

a = 2; b = -100; c = -1000;
Δ = b2-4ac
Δ = -1002-4·2·(-1000)
Δ = 18000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18000}=\sqrt{3600*5}=\sqrt{3600}*\sqrt{5}=60\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-60\sqrt{5}}{2*2}=\frac{100-60\sqrt{5}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+60\sqrt{5}}{2*2}=\frac{100+60\sqrt{5}}{4}
$